456B - Fedya and Maths - CodeForces Solution


math number theory *1200

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Python Code:

def main():
    n = int(input()) 
    if n%4==0:
        print("4\n");
    else:
        print("0\n");
        
main()
		  			 	 		  		 			  		 	 				

C++ Code:

#include <bits/stdc++.h>
using namespace std;

int main()
{
    string n; cin>>n;
    if((n[n.size()-2]-'0')%2==0){
        if((n[n.size()-1]-'0')==0||(n[n.size()-1]-'0')==4||(n[n.size()-1]-'0')==8)
            cout<<4;
        else
            cout<<0;
    }
    else{
        if((n[n.size()-1]-'0')==2||(n[n.size()-1]-'0')==6)
            cout<<4;
        else
            cout<<0;
    }
    return 0;
}


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